This article is a feature test - tries to test different behaviors of Markdown, code and math.

Is this section being rendered correctly? This Hero content was written with Markdown.

# Code block and output

for i in range(5):
    print(f'Hello, {i}')

def hello_world():
    print('hello world')

Hello, 0

Hello, 1

Hello, 2

Hello, 3

Hello, 4

# Stdout, stderr and runtime error

import sys

for i in range(10):
    if i % 2 == 0:
        print(f'Hello, {i}')
    else:
        print(f'Hello, {i}', file=sys.stderr)

x = None
x.doSomeMethodThatDoesNotExist()

Hello, 0

Hello, 2

Hello, 4

Hello, 6

Hello, 8

Hello, 1

Hello, 3

Hello, 5

Hello, 7

Hello, 9

import matplotlib.pyplot as plt
import numpy as np
import pandas as pd

# Generate random data for a plot
x = np.linspace(0, 10, 100)
y = np.sin(x) + np.random.normal(scale=0.1, size=len(x))

plt.figure(figsize=(8, 5))
plt.plot(x, y, label="Noisy Sine Wave", color="blue", linewidth=2)
plt.xlabel("X Axis")
plt.ylabel("Y Axis")
plt.title("Sample Matplotlib Plot")
plt.legend()
plt.grid(True)
plt.show()

# Generate a sample DataFrame
data = {
    "A": np.random.randint(0, 100, 10),
    "B": np.random.rand(10),
    "C": np.random.choice(["Yes", "No"], 10),
}
df = pd.DataFrame(data)

# Display DataFrame
df

Display Output

Display Output

	A	B	C
0	42	0.563690	Yes
1	83	0.158875	Yes
2	63	0.461055	Yes
3	85	0.535424	Yes
4	59	0.870812	Yes
5	41	0.623846	No
6	20	0.049943	No
7	60	0.206974	No
8	49	0.563570	No
9	72	0.964520	No

print('<h1>Hello world!</h1>')
print('<h1>Hello world!</h1>')

<h1>Hello world!</h1>

<h1>Hello world!</h1>

Tests on Markdown features

• Bullet point 1
• Bullet point 2
  • Nested bullet point 2.1
    • Nested bullet point 2.1.1
    • Nested bullet point 2.1.2
• Bullet point 3

1. Bullet point 1
2. Bullet point 2
   1. Bullet point 2.1
   2. Bullet point 2.2
      1. Bullet point 2.2.1
      2. Bullet point 2.2.2
3. Bullet point 3
4. Bullet point 4

• [x] Write the press release
• [ ] Update the website
• [ ] Contact the media

Hello world, this is a code block. Lorem ipsum dolor sit amet, consectetur adipiscing elit.

Code block without language description:

function extractAttachments(blob) {
  const attachments = Object
    .entries(blob)
    .map(([identifier, attachment]) => {
      const mime = Object.keys(attachment)[0];
      const data = Buffer.from(attachment[mime], 'base64');
      const meta = probe.sync(data);

      return {
        identifier,
        meta,
        data,
      };
    });

  return attachments;
}

Code block with language description:

function extractAttachments(blob) {
  const attachments = Object
    .entries(blob)
    .map(([identifier, attachment]) => {
      const mime = Object.keys(attachment)[0];
      const data = Buffer.from(attachment[mime], 'base64');
      const meta = probe.sync(data);

      return {
        identifier,
        meta,
        data,
      };
    });

  return attachments;
}

Inline equation $\underset{n\to \mathrm{\infty }}{lim}\sum _{k=1}^n{\int }_0^1\frac{d}{dx}(e^{-x^2}\cos \left(\pi kx\right))dx+\prod _{m=1}^{\mathrm{\infty }}(1+\frac{1}{m^2})+{\oint }_{\gamma }\frac{z^n}{(z-a)(z-b)}dz=\left[\begin{array}{ccc}{\int }_0^{\pi }\sin (x)dx& \sum _{k=1}^{\mathrm{\infty }}\frac{1}{k^2}& \zeta (3)\\ e^{i\pi }+1& \mathrm{\Gamma }(n)& \underset{x\to 0}{lim}\frac{\sin x}{x}\\ \sqrt[3]{\frac{a+b}{c}}& \log (1+\sum _{n=1}^{\mathrm{\infty }}\frac{(-1{)}^n}{n})& det\left(\begin{array}{cc}1& 2\\ 3& 4\end{array}\right)\end{array}\right]$ - yeah that was complexicated

Display math: